The undead existed in Scandinavian mythology. They drew special runes on gravestones so that the dead would not crawl out of their graves and rob everyone.
Dude ZagorathAus created a poll and got the corresponding result (77% NO). Very primitive flirting with the public from you. I did not like it.
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To be fair, Herios wasn’t the one who revived this thread after it had been effectively dead for nearly 3 weeks.
Yeah, unfortunately that pool does not have enough participation to be relevant we have less than 100 participants vs thousands of players
And even with so few, it means 1/4 would be in favor of it which I think is a lot
Pretty sure that a pool asking to add the Chinese pantheon before it was made would have approximately the same result
The truth is many people cannot foresee an idea of something new they could like, they only learn to like it once they see the finished product
Drow are in many games just dark elves
And dark elves exist in Norse mythology,
Drow are very specifically D&Ds dark elves.
And as I said, there are indicators (but no solid proof) that dark elves and dwarves in norse mythology are the same thing.
per now i want a dislike button for posts like this…
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I mean, your are never getting 100% sample size in any sort of poll, and most of the casual playerbase dont engage in any sort of forums so you tend to get players more invovled in the game (which makes sense, they care enough to get to here). With all that said, you have to go from is what you can get, which btw was to show this “majority” you called upon didnt seem to exist.
Cant really turn back on results and call upon a “hidden population” that would agree/disagree with Y or X since theres not evidence what would they back up.
While its true people dont like change, thats also an argument in favor of not forcing sudden change onto a playerbase and risk loosing players.
You would still have to subdivide your 1/4 into which specific new pantheon to add so its gonna be way way lower. The actual equivalent would be a poll asking for a 5th civ and then subdividing to getting china.
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Actually, the sample size is not a problem. A One-Sample Proportion Test:
z = (p̂ - p0) / σ
Where p̂ is the sample result: 41/54 are against anything (13/54 voted in favour of at least 1 of the other options—I’m assuming @jepzczu, who was the only person to vote for both “none” and one of the others, intended only to vote for one of the others).
p0 is 0.5 (i.e., the result we would get if both options were equal)
σ is our standard deviation, calculated by sqrt(p0(p0-1)/54), which gives 0.068
Filling in that formula, we get z = 3.81
We probably want a 95% confidence interval, which means we need a probability of at least 0.95 once we reference a Z-table.
Cross-referencing that on a Z table and we get 0.99993. This is much greater than 0.95, so we can accept the hypothesis.
A couple of points: you may notice that this test doesn’t use the size of the total population. That’s because it is actually designed for cases when the population is much greater than the sample size; it assumes a theoretically infinite population. Though if anyone else wants to try running a different type of statistical tool, I was going to use a population of 2,000,000 to “steel man” it. One estimate I saw had an upper range of the number of units sold at about 900,000, and I made the assumption that (1) that estimate was based only on Steam numbers, and that (2) Steam represents about 50% of the playerbase. So I rounded the 900,000 up to 1 million, and then doubled it.
The second point is that although it is statistically sound, there is one obvious potential problem here. The sample may not be representative. It’s a sample of users of the Age of Empires forums who play Age of Mythology, not taken at random from 54 Age of Mythology players. It is still, however, the best we’ve got, and the data are overwhelming in this case. And it would get even worse if you separated those who want one of the three proposed options in particular but not others. Then you’d be doing 48/54 or 47/54 instead of 41/54, which ends up with a z value over 5. None of the statistical tables I found even go that high, and the calculators I tried all just rounded it off to 1. A 100% chance our result is representative.
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